Multiple Choice Questions (MCQs)
Single Correct
Answer Type
Question 1. One requires 11 eV of energy to dissociate a carbon
monoxide molecule into carbon and oxygen atoms. The minimum frequency of the
appropriate electromagnetic radiation to achieve the dissociation lies
in
(a) visible region (b) infrared
region
(c) ultraviolet region (d) microwave
region
Solution:
Question 2.
Solution: (b)
Key concept: When a wave is
reflected from a denser medium or perfectly reflecting wall made with optically
inactive material, then the type of wave doesn’t change but only its phase
changes by 180° or π radian.
Question 3. Light with an energy flux of 20 W/cm2 falls on
a non-reflecting surface at normal incidence. If the surface has an area of 30
cm2, the total momentum delivered (for complete absorption) during 30
min is
(a) 36 x 10-5 kg-m/s (b) 36 x
10-4 kg-m/s
(c) 108 x 104 kg-m/s (d)
1.08 x 107 kg-m/s
Solution:
Question 4. The electric field intensity produced by the radiations
coming from a 100 W bulb at a 3 m distance is E. The electric field intensity
produced by the radiations coming from 50 W bulb at the same distance
is
Solution:
Question 5.
Solution: (d)
Key
concept: A changing electric field produces a changing magnetic field
and vice versa which gives rise to a transverse wave known as electromagnetic
wave. The time varying electric and magnetic field are mutually perpendicular to
each other and also perpendicular to the direction of propagation of this wave.
The electric vector is responsible for the optical effects of an EM wave and is
called the light vector.
Question 6. The ratio of contributions made by the electric field and
magnetic field components to the intensity of an EM wave is
Solution:
Hence the energy in electromagnetic wave is divided equally
between electric field vector and magnetic field vector.
It means the ratio
of contributions by the electric field and magnetic field components to the
intensity of an electromagnetic wave is 1:1.
Question 7. An EM wave radiates outwards from a dipole antenna, with
E0 as the amplitude of its electric field vector. The electric field
E0 which transports significant energy from the source falls off
as
Solution: (c) A diode antenna radiates the
electromagnetic waves outwards. The amplitude of electric field vector
(E0) which transports significant energy from the source falls
intensity inversely as the distance (r) from the antenna,
One or More Than One Correct Answer Type
Question
8.
Solution: (a, d) We are given that the
electric field vector of an electromagnetic wave travels in a vacuum along
z-direction as,
Question 9.
Solution: (a, b, c)
Question 10. A plane electromagnetic wave propagating along
x-direction can have the following pairs of E and B.
(a)
Ex, By (b) Ey,
Bz
(c) Bx,Ey (d)
Ez,By
Solution: (b,
d)
Here in the question electromagnetic wave is propagating
along x-direction. So, electro and magnetic field vectors should have either
y-direction or 2-direction.
Question 11. A charged particle oscillates about its mean equilibrium
position with a frequency of 109 Hz. The electromagnetic waves
produced
(a) will have frequency of 109
Hz
(b) will have frequency of 2 x 109
Hz
(c) will have wavelength of 0.3 m
(d) fall in the region of radio waves
Solution:
(a, c, d)
Here we are given the frequency by which the charged particles
oscillates about its mean equilibrium position, it is equal to 109
Hz. The frequency of electromagnetic waves produced by a charged particle is
equal to the frequency by which it oscillates about its mean equilibrium
position.
So, frequency of electromagnetic waves produced by the charged
particle is v= 109 Hz.
Question 12. The source of electromagnetic waves can be a
charge
(a) moving with a constant
velocity
(b) moving in a circular
orbit
(c) at rest
(d) falling in an
electric field
Solution: (b, d)
Key
concept:
Here, in option (b) charge is moving in a circular orbit.
In circular
motion, the direction of the motion of charge is changing continuously, thus it
is an accelerated motion and this option is correct.
In option (d), the
charge is falling in electric field. If a charged particle is moving in electric
field it experiences a force or we can say it accelerates. We know an
accelerating charge particle radiates electromagnetic waves. Hence option (d) is
also correct.
Also, we know that a charge starts accelerating when it falls
in an electric field.
Important points:
Question 13. An EM wave of intensity I falls on a surface kept
in vacuum and exerts radiation pressure p on it. Which of the following are
true?
(a) Radiation pressure is I/c if the wave is totally
absorbed
(b) Radiation pressure is —I/c if the wave is
totally reflected
(c) Radiation pressure is 2I/c if the
wave is totally reflected
(d) Radiation pressure is in the
range I/c < p < 2I/c for real surfaces
Solution: (a, c, d)
Key concept: Radiation pressure
(p) is the force exerted by electromagnetic wave on unit area of the surface,
i.e., rate of change of momentum per unit area of the surface.
Let us
consider a surface exposed to electromagnetic radiation as shown in figure. The
radiation is falling normally on the surface. Further, intensity of radiation is
I and area of surface exposed to radiation is A.
Very Short Answer Type Questions
Question 14. Why
is the orientation of the portable radio with respect to broadcasting station
important?
Solution: The electromagnetic waves are
plane polarised, so the receiving antenna should be parallel to the vibration of
the electric or magnetic field of the wave. So the receiving antenna should be
parallel to electric/magnetic part of the wave. That is why the orientation of
the portable radio with respect to broadcasting station is important.
Question 15. Why does microwave oven heats up a food item containing
water molecules most efficiently?
Solution: The
microwave oven heats up the food items containing water molecules most
efficiently because the frequency of microwaves matches the resonant frequency
of water molecules.
Question 16. The charge on a parallel plate capacitor varies as
q=q0 cos 2πvt. The plates are very large and close together
(area = A, separation = d). Neglecting the edge effects, find the displacement
current through the capacitor.
Solution:
Question 17. A variable frequency AC source is connected to a
capacitor. How will the displacement current change with decrease in
frequency?
Solution:
It means the displacement current decreases as the conduction
current is equal to the displacement current.
Question 18. The magnetic field of a beam emerging from a fitter
facing a flood light is given by B0= 12 x
10-8 sin (1.20 x 107z- 3.60 x 1015 t) T What is
the average intensity of the beam?
Solution:
Question 19.
Solution:
Question 20. Professor CV Raman surprised his students by suspending
freely a tiny light ball in a transparent vacuum chamber by shining a laser beam
on it. Which property of EM waves was he exhibiting? Give one more example of
this property.
Solution: The properties of an
electromagnetic wave is same as other waves. Like other wave an electromagnetic
wave also carries energy and momentum. Since, it carries momentum, an
electromagnetic wave also exerts pressure called radiation pressure. This
property of electromagnetic waves helped professor C V Raman surprised his
students by suspending freely a tiny light ball in a transparent vacuum chamber
by shining a laser beam on it.
Short Answer Type Questions
Question
21.
Solution:
Question 22. Electromagnetic waves with
wavelength
(i) λ1, is used in satellite
communication.
(ii) λ2, is used to kill germs in
water purifier.
(iii) λ3, is used to detect
leakage of oil in underground pipelines.
(iv)
λ4, is used to improve visibility in runways during fog and mist
conditions.
(a) Identify and name the part of
electromagnetic spectrum to which these radiations belong.
(b) Arrange these wavelengths in ascending order of their
magnitude.
(c) Write one more application of
each.
Solution: (a) (i) In satellite
communications, microwave is widely used. Hence λ1, is the wavelength
of microwave.
(ii) In water purifier, ultraviolet rays are used to kill
germs. So, λ2 is the wavelength of UV rays.
(iii) X-rays are used
to detect leakage of oil in underground pipelines. So, λ3 is the
wavelength of X-rays.
(iv) Infrared rays are used to improve visibility on
runways during fog and mist conditions. So, it is the wavelength of infrared
waves.
(b) Wavelength of X-rays < wavelength of UV < wavelength of
infrared < wavelength of microwave.
=>
λ3<λ2<λ4<λ1
Question 23.
Solution:
Question 24. You are given a 2 μF parallel plate capacitor. How would
you establish an instantaneous displacement current of 1 mA in the space between
its plates?
Solution:
Question 25. Show that the radiation pressure exerted by an EM wave
of intensity I on a surface kept in vacuum is I/C.
Solution: Let us consider a surface exposed to electromagnetic
radiation. The radiation is falling normally on the surface. Further, intensity
of radiation is I and area of surface exposed to radiation is A.
Question 26. What happens to the intensity of light from a bulb if
the distance from the bulb is doubled? As a laser beam travels across the length
of room, its intensity essentially remains constant.
What
geometrical characteristic of LASER beam is responsible for the constant
intensity which is missing in the case of light from the
bulb?
Solution: We know intensity of light from a
point source I α 1/r2, r is the distance from point source.
As the
distance is doubled, so the intensity becomes one-fourth the initial value. But
in case of laser it does not spread, so its intensity remain same.
Some
geometrical characteristics of LASER beam which are responsible for the constant
intensity is
(i) Unidirection (ii) Monochromatic
(iii) Coherent light (iv)
Highly collimated
These characteristics are missing in the case of normal
light from the bulb.
Question 27. Even though an electric field E exerts a force qE on a
charged particle yet electric field of an EM wave does not contribute to the
radiation pressure (but transfers energy). Explain.
Solution: The electric field of an electromagnetic wave is an
oscillation field. It exerts electric force on a charged particle, but this
electric force averaged over an integral number of cycles is zero, since its
direction changes every half cycle. Hence, electric field is not responsible for
radiation pressure though it transfer the energy. In fact, radiation pressure
appears as a result of the action of the magnetic field of the wave on the
electric currents induced by the electric field of the same wave.
Long Answer Type Questions
Question
28.
Solution:
Question 29.
Solution:
Question 30.
(i) Calculate the displacement current density
inside the cable.
(ii) Integrate the displacement current
density across the cross-section of the cable to find the total displacement
current ld.
(iii) Compare the conduction current
I0 with the displacement current
I0d.
Solution:
Question 31.
Solution:
Question 32.
Solution: (i) Total energy carried by
electromagnetic wave is due to electric field vector and magnetic field vector.
In electromagnetic wave, E and B vary from point to point and from moment to
moment.