a) Solubility
b) Concentration
c) Molarity
d) Molality
Answer: a) Solubility
Explanation: Solubility refers to the maximum amount of solute
that can dissolve in a given solvent at a specific temperature.
a) Moles of solute per liter of solution
b) Moles of solute per kilogram of solvent
c) Mass of solute per volume of solution
d) Volume of solute per mass of solvent
Answer: b) Moles of solute per kilogram of solvent
Explanation: Molality is the number of moles of solute per
kilogram of solvent.
a) Solubility of gases increases with temperature
b) Solubility of gases decreases with temperature
c) Solubility remains unaffected by temperature
d) Solubility first increases and then decreases with temperature
Answer: b) Solubility of gases decreases with temperature
Explanation: As temperature increases, the solubility of gases
in liquids decreases, because gases tend to escape from the solution at higher
temperatures.
a) Boiling point
b) Freezing point
c) Osmotic pressure
d) All of the above
Answer: d) All of the above
Explanation: Colligative properties, including boiling point
elevation, freezing point depression, and osmotic pressure, depend on the number
of solute particles in the solution, not their identity.
a) The temperature
b) The concentration of solute
c) The molecular weight of the solute
d) The polarity of the solvent
Answer: b) The concentration of solute
Explanation: In an ideal solution, the vapor pressure of the
solvent decreases as the concentration of solute increases.
a) The enthalpy of mixing is zero
b) The volume change on mixing is zero
c) The solute and solvent obey Raoult's law
d) All of the above
Answer: d) All of the above
Explanation: Ideal solutions obey Raoult's law, have zero
enthalpy of mixing, and no volume change upon mixing.
a) 2°C
b) 3°C
c) 5°C
d) 7°C
Answer: b) 3°C
Explanation: Freezing point depression is the difference
between the freezing point of the pure solvent and the solution. So, 5°C - 2°C =
3°C.
a)
b)
c)
d)
Answer: a)
Explanation: In an ideal solution, the partial vapor pressure
of the solvent is directly proportional to its mole fraction
and its vapor pressure in the pure state
.
a) Raoult's Law
b) Henry's Law
c) Dalton's Law
d) Avogadro's Law
Answer: a) Raoult's Law
Explanation: Raoult's Law states that the vapor pressure of a
solvent in a solution is directly proportional to the mole fraction of the
solvent in the solution.
a) Filtration
b) Simple distillation
c) Fractional distillation
d) Chromatography
Answer: c) Fractional distillation
Explanation: Fractional distillation is used to separate
mixtures of liquids with different boiling points.
a) 0
b) 1
c) 2
d) Infinite
Answer: b) 1
Explanation: For a non-electrolyte solute, which does not
dissociate in solution, the van't Hoff factor (
)
is 1.
a) Moles of solute per liter of solution
b) Moles of solute per kilogram of solvent
c) Mass of solute per volume of solution
d) Volume of solute per mass of solvent
Answer: a) Moles of solute per liter of solution
Explanation: Molarity is the number of moles of solute
dissolved in one liter of solution.
a) Hypertonic
b) Hypotonic
c) Isotonic
d) Saturated
Answer: c) Isotonic
Explanation: An isotonic solution has the same concentration of
solute as the cytoplasm of a cell, which prevents the cell from swelling or
shrinking.
a) Moles of solute per liter of solution
b) Moles of solute per kilogram of solvent
c) Grams of solute per liter of solution
d) Grams of solute per kilogram of solvent
Answer: b) Moles of solute per kilogram of solvent
Explanation: Molality is expressed as moles of solute per
kilogram of solvent.
a) The temperature increases
b) The solute is added to the solvent
c) The solute is volatile
d) The solute is highly concentrated
Answer: b) The solute is added to the solvent
Explanation: Adding a non-volatile solute to a solvent lowers
the vapor pressure of the solvent.
a) Benzene and toluene
b) Water and ethanol
c) Acetone and chloroform
d) None of the above
Answer: a) Benzene and toluene
Explanation: Benzene and toluene form an ideal solution as they
obey Raoult's law throughout all concentrations.
a)
b)
c)
d)
Answer: c)
Explanation: The depression in freezing point is given by
,
where
is the cryoscopic constant,
is the molality, and
is the van’t Hoff factor.
a) Freezing point depression
b) Osmotic pressure
c) Boiling point elevation
d) Solubility
Answer: d) Solubility
Explanation: Solubility is not a colligative property; it
depends on the nature of the solute, unlike colligative properties that depend
on the number of solute particles.
a) 0.5 mol NaCl in water
b) 0.5 mol KNO3 in water
c) 0.5 mol glucose in water
d) 0.5 mol H2O in water
Answer: b) 0.5 mol KNO3 in water
Explanation: KNO3 dissociates into three ions (K+, NO3-, and
one more ion in the solution), leading to a higher boiling point elevation
compared to non-electrolytes.
a) The temperature
b) The number of solute particles
c) The volume of solution
d) All of the above
Answer: d) All of the above
Explanation: Osmotic pressure depends on temperature, the
concentration of solute particles, and the volume of the solution.
a) 1
b) 2
c) 3
d) 4
Answer: b) 2
Explanation: NaCl dissociates into two ions (Na+ and Cl-) in
water, so its van't Hoff factor is 2.
a) The intermolecular forces between solute and solvent are weaker than between
the solvent molecules
b) The intermolecular forces between solute and solvent are stronger than
between the solvent molecules
c) The solute is non-volatile
d) The solution is ideal
Answer: b) The intermolecular forces between solute and solvent
are stronger than between the solvent molecules
Explanation: Negative deviations occur when solute-solvent
interactions are stronger than solvent-solvent interactions, reducing the vapor
pressure.
a) 0.5 M
b) 1 M
c) 2.5 M
d) 3 M
Answer: a) 0.5 M
Explanation: Molarity
. Moles of
NaOH =
= 0.125
mol. So, molarity
.
a) 1 mol NaCl in 1 kg of water
b) 1 mol K2SO4 in 1 kg of water
c) 1 mol glucose in 1 kg of water
d) 1 mol urea in 1 kg of water
Answer: b) 1 mol K2SO4 in 1 kg of water
Explanation: K2SO4 dissociates into 3 ions (2 K+ and 1 SO4 2-),
leading to a higher depression in freezing point than glucose or urea.
a) Freezing point depression
b) Boiling point elevation
c) Osmotic pressure
d) All of the above
Answer: d) All of the above
Explanation: Freezing point depression, boiling point
elevation, and osmotic pressure can all be used to determine the molecular
weight of a solute.
a) 0.25
b) 0.5
c) 0.75
d) 1.0
Answer: a) 0.25
Explanation: Using Raoult's Law,
.
Here,
.
Substituting the given values:
, so
.
a) It will decrease
b) It will increase
c) It will remain constant
d) It will first increase, then decrease
Answer: b) It will increase
Explanation: Osmotic pressure is directly proportional to
temperature, so increasing the temperature increases the osmotic pressure.
a) Vapor pressure of the solution is higher than that of the pure solvent
b) Vapor pressure of the solution is lower than that of the pure solvent
c) The boiling point of the solution is lower than that of the pure solvent
d) The freezing point of the solution is higher than that of the pure solvent
Answer: b) Vapor pressure of the solution is lower than that of
the pure solvent
Explanation: The addition of a non-volatile solute to a solvent
lowers the vapor pressure of the solvent.
a) 1
b) 2
c) 3
d) 4
Answer: c) 3
Explanation: K2SO4 dissociates into three ions (2 K+ and 1 SO4
2-) in water, so its van't Hoff factor is 3.
a) Barometer
b) Manometer
c) Membrane filter
d) Osmometer
Answer: d) Osmometer
Explanation: An osmometer is an instrument used to measure the
osmotic pressure of a solution.
a) Raoult’s Law
b) Henry’s Law
c) Beckmann’s Law
d) Cryoscopic Law
Answer: d) Cryoscopic Law
Explanation: The cryoscopic law states that the depression in
freezing point is directly proportional to the molal concentration of the
solution.
a) The intermolecular forces between solute and solvent are weaker than between
the solvent molecules
b) The intermolecular forces between solute and solvent are stronger than
between the solvent molecules
c) The solution behaves ideally
d) The solution has a higher vapor pressure than predicted
Answer: a) The intermolecular forces between solute and solvent
are weaker than between the solvent molecules
Explanation: Positive deviations occur when solute-solvent
interactions are weaker than solvent-solvent interactions, leading to a higher
vapor pressure than predicted by Raoult’s Law.
a) 1 mol NaCl in 1 kg of water
b) 1 mol KNO3 in 1 kg of water
c) 1 mol glucose in 1 kg of water
d) 1 mol urea in 1 kg of water
Answer: b) 1 mol KNO3 in 1 kg of water
Explanation: KNO3 dissociates into three ions, giving the
highest number of particles in solution, which leads to the greatest elevation
in boiling point.
a)
b)
c)
d)
Answer: a)
Explanation: The freezing point depression is proportional to
the molality of the solution, as given by the equation
,
where
is the cryoscopic constant.
a)
b)
c)
d)
Answer: a)
Explanation: Molarity is defined as the number of moles of
solute per liter of solution.
a) 0.5 atm
b) 1.0 atm
c) 2.0 atm
d) 4.0 atm
Answer: a) 0.5 atm
Explanation: Osmotic pressure is inversely proportional to the
volume of the solution. If the volume is doubled, the osmotic pressure will be
halved.
a) 0.5 molal
b) 0.5 molar
c) 0.5 normal
d) None of the above
Answer: b) 0.5 molar
Explanation: A molar solution contains 1 mole of solute per
liter of solution. So, 0.5 moles per liter is a 0.5 molar solution.
a) The enthalpy of mixing is zero
b) The volume of mixing is zero
c) The solution obeys Raoult’s law at all concentrations
d) The solution exhibits deviations from Raoult's law
Answer: d) The solution exhibits deviations from Raoult's law
Explanation: An ideal solution obeys Raoult’s law at all
concentrations and shows no deviations in terms of enthalpy or volume of mixing.
a) Mole fraction of the solute
b) Molality of the solution
c) Volume of the solution
d) Density of the solution
Answer: b) Molality of the solution
Explanation: Boiling point elevation is directly proportional
to the molality of the solution, as given by the equation
.
a) Raoult’s Law
b) Henry’s Law
c) Dalton’s Law
d) Gay-Lussac’s Law
Answer: a) Raoult’s Law
Explanation: Raoult's Law relates the vapor pressure of a
solvent in a solution to its mole fraction.
a) NaCl
b) KNO3
c) C6H12O6 (glucose)
d) Urea
Answer: b) KNO3
Explanation: KNO3 dissociates into 3 ions (2 K+ and 1 NO3-),
resulting in the greatest depression of the freezing point, compared to the
others.
a) 1.0 mol
b) 0.5 mol
c) 2.0 mol
d) 0.1 mol
Answer: b) 0.5 mol
Explanation: Moles of solute = molarity × volume (in liters).
So,
.
a) Increasing the volume
b) Increasing the temperature
c) Decreasing the volume
d) Decreasing the temperature
Answer: b) Increasing the temperature
Explanation: Osmotic pressure is directly proportional to
temperature, so increasing temperature will have the largest effect.
a) 1.0 M
b) 0.5 M
c) 2.0 M
d) 1.0 N
Answer: a) 1.0 M
Explanation: For monoprotic acids, normality is equal to
molarity, so the molarity is also 1.0 M.
a) Water and acetone
b) Water and benzene
c) Water and chloroform
d) Water and ethanol
Answer: c) Water and chloroform
Explanation: Water and chloroform exhibit negative deviations
because their intermolecular forces are stronger than the forces between the
solvent molecules.
a)
b)
c)
d)
Answer: a)
Explanation: The depression in freezing point (
)
is directly proportional to the molality (
)
of the solution.
a) NaCl does not dissociate
b) It shows negative deviations from Raoult's law
c) It does not show any deviation from Raoult's law
d) NaCl dissociates into two ions in water
Answer: d) NaCl dissociates into two ions in water
Explanation: NaCl dissociates into Na+ and Cl- ions in water,
which affects the properties of the solution.
a) It follows Raoult’s law over the entire range of concentration
b) It exhibits a positive deviation from Raoult's law
c) It exhibits a negative deviation from Raoult's law
d) The vapor pressure of the solution is always greater than that of the pure
solvent
Answer: a) It follows Raoult’s law over the entire range of
concentration
Explanation: An ideal solution follows Raoult's law over the
entire concentration range.
a) Nature of the solvent
b) Nature of the solute
c) Temperature
d) Concentration of the solute
Answer: b) Nature of the solute
Explanation: The nature of the solute does not directly affect
the vapor pressure of the solvent; it is the concentration of the solute and
temperature that affect it.
a) Freezing point depression
b) Boiling point elevation
c) Osmotic pressure
d) All of the above
Answer: d) All of the above
Explanation: The molar mass of an unknown solute can be
determined using freezing point depression, boiling point elevation, and osmotic
pressure, as they all depend on the number of particles in solution.