a) CH3NH2
b) (CH3)2NH
c) (CH3)3N
d) NH3
Answer: a) CH3NH2
Explanation: CH3NH2 (methylamine) is a primary amine, where one
alkyl group (methyl group) is attached to the nitrogen atom.
a) They are acidic in nature
b) They react with acids to form salts
c) They do not form hydrogen bonds
d) They are non-basic
Answer: b) They react with acids to form salts
Explanation: Amines are basic in nature and react with acids to
form amine salts, e.g., methylamine reacts with hydrochloric acid to form
methylammonium chloride.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Ethylamine
Answer: c) Dimethylamine
Explanation: Dimethylamine is more basic than aniline and
methylamine because the electron-donating effect of the two methyl groups
increases the electron density on the nitrogen atom, making it more basic.
a) Ethylamine
b) N-Ethylamine
c) Ethanolamine
d) Aminoethane
Answer: a) Ethylamine
Explanation: CH3CH2NH2 is named ethylamine, where the amine
group is attached to an ethyl group.
a) Alcohol
b) Ammonium salt
c) Amino acid
d) Alkene
Answer: b) Ammonium salt
Explanation: When an amine reacts with an alkyl halide, an
ammonium salt is formed due to nucleophilic substitution.
a) Acetylation
b) Hinsberg test
c) Bromine water test
d) Schiff's test
Answer: b) Hinsberg test
Explanation: The Hinsberg test is used to distinguish primary
amines from secondary and tertiary amines by forming soluble or insoluble
derivatives.
a) CH3NH2
b) (CH3)2NH
c) (CH3)3N
d) NH3
Answer: b) (CH3)2NH
Explanation: (CH3)2NH (dimethylamine) is a secondary amine,
where two methyl groups are attached to the nitrogen atom.
a) Benzene
b) Phenyl amine
c) 2,4,6-Tribromoaniline
d) Benzoic acid
Answer: c) 2,4,6-Tribromoaniline
Explanation: When aniline reacts with bromine water, a
substitution reaction occurs, resulting in the formation of
2,4,6-tribromoaniline.
a) Ammonia
b) Aniline
c) Methylamine
d) All of the above
Answer: d) All of the above
Explanation: All amines (ammonia, aniline, methylamine) act as
Lewis bases because nitrogen has a lone pair of electrons, which can donate to
an electron-deficient species.
a) Reduction of nitrobenzene
b) Nitration of benzene
c) Friedel-Crafts acylation
d) Hydrolysis of benzamide
Answer: a) Reduction of nitrobenzene
Explanation: Aniline can be prepared by the reduction of
nitrobenzene using reducing agents like tin and hydrochloric acid.
a) Reduction
b) Oxidation
c) Hydrolysis
d) Dehydration
Answer: a) Reduction
Explanation: Nitriles can be reduced to amines using reducing
agents like LiAlH4 or catalytic hydrogenation.
a) Aniline > Ethylamine > Methylamine
b) Methylamine > Ethylamine > Aniline
c) Ethylamine > Methylamine > Aniline
d) Methylamine > Aniline > Ethylamine
Answer: b) Methylamine > Ethylamine > Aniline
Explanation: Methylamine is more basic than ethylamine due to
the electron-donating effect of the methyl group. Aniline is less basic because
the lone pair on nitrogen is delocalized into the aromatic ring.
a) Aniline
b) Methylamine
c) Ethylamine
d) Aromatic amines
Answer: b) Methylamine
Explanation: The Hofmann degradation reaction involves the
removal of the amine group from primary amides, resulting in the formation of a
primary amine with one fewer carbon atom. Methylamine undergoes this reaction.
a) Aniline
b) Butylamine
c) Dimethylamine
d) Trimethylamine
Answer: b) Butylamine
Explanation: Butylamine (C4H9NH2) is a primary amine, with a
single butyl group attached to the nitrogen atom.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Ethylamine
Answer: a) Aniline
Explanation: Aniline (C6H5NH2) can undergo diazotization to
form a diazonium salt, which is a characteristic reaction of primary aromatic
amines.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Ethylamine
Answer: b) Methylamine
Explanation: Methylamine, being a primary aliphatic amine, does
not readily form an amide with an acyl chloride under normal conditions.
a) They are highly basic
b) They do not undergo the Hinsberg test
c) They are weakly basic
d) They undergo electrophilic substitution reactions easily
Answer: b) They do not undergo the Hinsberg test
Explanation: Tertiary amines do not react with benzene sulfonyl
chloride in the Hinsberg test, which is used to distinguish primary and
secondary amines.
a) Ammonium salt
b) Amide
c) Alcohol
d) Nitrile
Answer: b) Amide
Explanation: When an amine reacts with an acid chloride, an
amide is formed through nucleophilic acyl substitution.
a) Benzene
b) Benzoic acid
c) Diazonium salt
d) Nitrobenzene
Answer: c) Diazonium salt
Explanation: Aniline reacts with nitrous acid to form a
diazonium salt, which is an important intermediate in organic synthesis.
a) Alkene
b) Primary amine
c) Tertiary amine
d) Ammonium salt
Answer: b) Primary amine
Explanation: Ammonia reacts with an alkyl halide to form a
primary amine through a nucleophilic substitution reaction.
a) Dimethylamine
b) Methylamine
c) Ethylamine
d) N-Methylamine
Answer: a) Dimethylamine
Explanation: CH3NHCH3 is dimethylamine, where two methyl groups
are attached to the nitrogen atom.
a) It decreases the basicity
b) It increases the basicity
c) It does not affect the basicity
d) It makes amines acidic
Answer: b) It increases the basicity
Explanation: Electron-donating groups increase the electron
density on nitrogen, enhancing its ability to donate electrons and thus
increasing basicity.
a) Benzenamine
b) Benzylamine
c) Phenylamine
d) Aniline
Answer: b) Benzylamine
Explanation: C6H5CH2NH2 is benzylamine, where the amine group
is attached to a benzyl group (C6H5CH2-).
a) Methylamine
b) Aniline
c) Dimethylamine
d) Butylamine
Answer: b) Aniline
Explanation: Aniline reacts with bromine in water to form
2,4,6-tribromoaniline, a characteristic reaction of aromatic amines.
a) Amines are acidic in nature
b) Amines do not form hydrogen bonds
c) Amines are basic in nature
d) Amines are non-polar
Answer: c) Amines are basic in nature
Explanation: Amines are basic due to the lone pair of electrons
on the nitrogen atom that can accept protons.
a) Reduction with LiAlH4
b) Substitution with ammonia
c) Dehydrohalogenation
d) Nitration
Answer: b) Substitution with ammonia
Explanation: Alkyl halides react with ammonia to form primary
amines through a nucleophilic substitution reaction.
a) Methylamine
b) Aniline
c) Dimethylamine
d) Ethylamine
Answer: b) Aniline
Explanation: Aniline is widely used in the manufacture of dyes
and other organic compounds, including pharmaceuticals.
a) Methylamine
b) Aniline
c) Lidocaine
d) Dimethylamine
Answer: c) Lidocaine
Explanation: Lidocaine, a derivative of an amine, is commonly
used as a local anesthetic in medical practices.
a) Diazonium salt
b) Amide
c) Alkene
d) Alcohol
Answer: a) Diazonium salt
Explanation: Primary aromatic amines react with nitrous acid to
form diazonium salts, which are intermediates in azo dye synthesis.
a) Dimethylamine > Methylamine > Aniline
b) Methylamine > Dimethylamine > Aniline
c) Aniline > Methylamine > Dimethylamine
d) Aniline > Dimethylamine > Methylamine
Answer: a) Dimethylamine > Methylamine > Aniline
Explanation: Dimethylamine is the most basic because of the
strong electron-donating effect of the methyl groups, followed by methylamine
and then aniline, which has its lone pair of electrons delocalized into the
aromatic ring.
a) Benzenamine
b) Aniline
c) Phenylamine
d) Aminobenzene
Answer: b) Aniline
Explanation: C6H5NH2 is aniline, an aromatic amine, where the
amine group is directly attached to a benzene ring.
a) LiAlH4
b) NaOH
c) HCl
d) H2O
Answer: a) LiAlH4
Explanation: Lithium aluminium hydride (LiAlH4) is used to
reduce nitriles to amines.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Ethylamine
Answer: a) Aniline
Explanation: Aniline is used in the preparation of various
dyes, particularly azo dyes.
a) Dimethylamine
b) Aniline
c) Ethylamine
d) Benzylamine
Answer: b) Aniline
Explanation: Aniline is formed by the reduction of nitrobenzene
using reducing agents like tin and hydrochloric acid.
a) Alkyl groups decrease the basicity
b) Alkyl groups do not affect the basicity
c) Alkyl groups increase the basicity
d) Alkyl groups increase the acidity
Answer: c) Alkyl groups increase the basicity
Explanation: Alkyl groups are electron-donating groups and
increase the electron density on nitrogen, thus increasing the basicity of
amines.
a) CH3-NH-CH3
b) CH3-CH2-NH2
c) CH3-NH2
d) (CH3)2NH
Answer: d) (CH3)2NH
Explanation: Dimethylamine is represented by (CH3)2NH, where
two methyl groups are attached to the nitrogen atom.
a) Amides
b) Ureides
c) Schiff base
d) Hydrazones
Answer: c) Schiff base
Explanation: Amines react with formaldehyde to form Schiff
bases (imines) through condensation reactions.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Ethylamine
Answer: b) Methylamine
Explanation: Methylamine undergoes Hofmann rearrangement to
produce methane.
a) Hydrogenation
b) Dehydrogenation
c) Nitration
d) Bromination
Answer: a) Hydrogenation
Explanation: Nitro compounds can be reduced to amines using
hydrogenation (H2) over a suitable catalyst.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Tertiary amines
Answer: c) Dimethylamine
Explanation: Dimethylamine is the most basic due to the
electron-donating effect of the two methyl groups.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Ethylamine
Answer: c) Dimethylamine
Explanation: Dimethylamine does not react with benzene sulfonyl
chloride in the Hinsberg test, differentiating it from primary and secondary
amines.
a) Polar covalent bond
b) Non-polar covalent bond
c) Ionic bond
d) Metallic bond
Answer: a) Polar covalent bond
Explanation: The bond between nitrogen and hydrogen in amines
is a polar covalent bond due to the electronegativity difference between
nitrogen and hydrogen.
a) Alcohol
b) Ammonium salt
c) Ether
d) Alkene
Answer: b) Ammonium salt
Explanation: Amines react with acids to form ammonium salts,
which are ionic compounds.
a) Aniline
b) Benzydamine
c) Phenylamine
d) Methylamine
Answer: d) Methylamine
Explanation: Methylamine is an aliphatic amine, while the other
options are aromatic amines.
a) Alkylation with an alkyl halide
b) Reduction with LiAlH4
c) Nitration with nitric acid
d) Dehydrohalogenation
Answer: a) Alkylation with an alkyl halide
Explanation: Secondary amines can be synthesized from primary
amines through alkylation with alkyl halides.
a) Methylamine
b) Aniline
c) Ethylamine
d) Dimethylamine
Answer: b) Aniline
Explanation: Aniline is used in the production of aspirin,
which is synthesized from salicylic acid and acetic acid.
a) Alkylated amine
b) Ammonium salt
c) Amide
d) Alcohol
Answer: a) Alkylated amine
Explanation: Amines react with alkyl halides to form alkylated
amines through nucleophilic substitution.
a) Methylamine
b) Dimethylamine
c) Aniline
d) Amino acids
Answer: d) Amino acids
Explanation: Amino acids, which contain amine groups, are the
building blocks of proteins.
a) Reaction with carboxylic acids to form salts
b) Reaction with halogens to form halides
c) Reaction with metals to form oxides
d) Reaction with nitrous acid to form diazonium salts
Answer: d) Reaction with nitrous acid to form diazonium salts
Explanation: Aromatic amines react with nitrous acid to form
diazonium salts, a characteristic reaction of amines.
a) Aniline
b) Methylamine
c) Dimethylamine
d) Ethylamine
Answer: b) Methylamine
Explanation: Methylamine, being a primary amine, is most likely
to undergo nucleophilic substitution with alkyl halides to form secondary
amines.