ROUTERA


Chapter 23 Scalar Or Dot Product Of Vectors

Class 12th Maths R S Aggarwal Solution



Exercise 23
Question 1.

Find when

i. and

ii. and

iii. and


Answer:

i)







Ans:


ii)







Ans: ⇒


iii)







Ans: ⇒



Question 2.

Find the value of λ for which and are perpendicular, where

i. and

ii. and

iii. and

iv. and


Answer:

i)




Since these two vectors are perpendicular,their dot product is zero.








Ans:


ii)




Since these two vectors are perpendicular,their dot product is zero.








Ans: λ = 3


iii)




Since these two vectors are perpendicular,their dot product is zero.








Ans: λ = - 2


iv)




Since these two vectors are perpendicular,their dot product is zero.








Ans: λ = - 2



Question 3.

i. If and show that is perpendicular to

ii. If and then show that and are orthogonal.


Answer:

i)








Now


= (4 × - 2) + (1 × 3) + ( - 1 × - 5) = - 8 + 3 + 5 = 0


Since the dot product of these two vectors is 0,the vector is perpendicular to


Hence,proved.


ii)








Now


= (6 × 4) + (2 × - 4) + ( - 8 × 2) = 24 - 8 - 16 = 0


Since the dot product of these two vectors is 0,the vector is perpendicular to


Hence,proved that and are orthogonal.



Question 4.

If and then find the value of λ so that and are orthogonal vectors.


Answer:



(





Now


Since these two vectors are orthogonal,their dot product is zero.


⇒ (6 × - 4) + ( - 2 × 0) + ( (7 + λ) × (7 - λ)) = 0
⇒ - 24 + 0 + (49 - λ2) = 0


⇒ λ2 = 25


⇒ λ = ±5


Ans: λ = ±5



Question 5.

Show that the vectors

and

are mutually perpendicular unit vectors.


Answer:

Let,





|| = || = || = 1


We have to show that :


L.H.S.





= R.H.S.


Hence,showed that vectors are mutually perpendicular unit vectors.



Question 6.

Let and

Find a vector which is perpendicular to both and and is such that


Answer:




Let


the vector which is perpendicular to both and










Solving equations 1,2,3 simultaneously we get


p = 7,q = - 7,r = - 7



Ans:



Question 7.

Let and

Find the projection of (i) on and (ii) on


Answer:



|| =


|| =




Projection of


Projection of


Ans: i)


ii)



Question 8.

Find the projection of in the direction of


Answer:

Let,




|| =



∴ The projection of


is:


Ans:10/3



Question 9.

Write the projection of vector along the vector


Answer:

Let,




|| =



∴ The projection of


is:


Ans:1



Question 10.

i. Find the projection of on if and

ii. Write the projection of the vector on the vector


Answer:

i)


|| =


Projection of on


=


=


ANS:8/7


ii) Sol:


Let,




|| =



∴ The projection of


is:


Ans: 0



Question 11.

Find the angle between the vectors and when

i. and

ii. and

iii. and


Answer:

i) and




|| =


|| =


We know that ,




⇒ (3 + 4 + 3) = 14cosθ


⇒ cosθ = 10/14


⇒ cosθ = 5/7


⇒ θ = cos - 1(5/7)


Ans: θ = cos - 1(5/7)


ii) and




|| =


|| =


We know that ,




⇒ (6 - 2 + 8) = √336 cosθ


⇒ cosθ = 12/√336


⇒ cosθ = √(144/336)


⇒ θ = cos - 1√ (3/7)


Ans: θ = cos - 1√ (3/7)


iii. and


Ans:




|| =


|| =


We know that ,




⇒ ( - 1) = 2 cosθ


⇒ cosθ = - 1/2


⇒ θ = cos - 1 - 1/2


⇒ θ = 120⁰


Ans: θ = 120⁰



Question 12.

If and then calculate the angle between and


Answer:





|| =


|| =


We know that ,




⇒ (35 - 4) = 50 cosθ


⇒ cosθ = 31/50


⇒ θ = cos - 1(31/50)


Ans: θ = cos - 1(31/50)



Question 13.

If is a unit vector such that find


Answer:

If is a unit vector


⇒ || = 1



⇒ ||2 - ||2 = 8


⇒ ||2 = 8 + 1 = 9


⇒ || = 3


Ans: || = 3



Question 14.

Find the angles which the vector makes with the coordinate axes.


Answer:

If we have a vector = a + b + c


then the angle with the x - axis =


the angle with the y - axis =


the angle with the z - axis =


Here, = 3 - 6 + 2



then the angle with the x - axis =


the angle with the y - axis =


the angle with the z - axis =


Ans:




Question 15.

Show that the vector is equally inclined to the coordinate axes.


Answer:

If we have a vector = a + b + c


then the angle with the x - axis =


the angle with the y - axis =


the angle with the z - axis =


Here,



then the angle with the x - axis =


the angle with the y - axis =


the angle with the z - axis =


Now since,


∴ the vector is equally inclined to the coordinate axes.


Hence,proved.



Question 16.

Find a vector of magnitude making an angle π/4 with x - axis, π/2 with y - axis and an acute angle θ with z - axis.


Answer:

|| = 5√2


l = cos α = cos π/4 = 1/√2


m = cos β = cos π/2 = 0


n = cosθ


we know that


l2 + m2 + n2 = 1






since the vector makes an acute angle with the z axis



= ||(l + m + n)


= 5√2(1/√2 + 1/√2)


= 5()


Ans: = 5()



Question 17.

Find the angle between and if and


Answer:





|| =


|| =


We know that ,




⇒ ( - 5 + 5) = cosθ


⇒ cosθ = 0


⇒ θ = cos - 1(0) = π/2


Ans: θ = π/2



Question 18.

Express the vector as sum of two vectors such that one is parallel to the vector and the other is perpendicular to


Answer:





&





⇒ λ = - 1








Ans:



Question 19.

Prove that where and


Answer:




Which is not possible hence




Question 20.

If and find the angle between and


Answer:










Ans:



Question 21.

Find the angle between and when

i. and

ii. and


Answer:

i)


We know that ,





⇒ cosθ = √3/2


⇒ θ = cos - 1(√3/2) = 30⁰ =


Ans: θ = cos - 1(√3/2) = 30⁰ =


ii)


We know that ,





⇒ cosθ = - 1/2


⇒ θ = cos - 1( - 1/2) = 120⁰ =


Ans: θ = cos - 1( - 1/2) = 120⁰ =



Question 22.

If and find


Answer:

We know that ,





⇒ cosθ = 4/6


⇒ cosθ = 2/3






Ans: √5



Question 23.

If and find and


Answer:

().() = 8








Ans:



Question 24.

If and are unit vectors inclined at an angle θ then prove that:

i.

ii.


Answer:

R.H.S:


)








= L.H.S


Hence, proved


ii)


R.H.S. =








⇒ tanθ/2 = L.H.S


Hence,proved.



Question 25.

The dot products of a vector with the vector and are 0, 5 and 8 respectively. Find the vector.


Answer:

Let the unknown vector be:



⇒ a + b - 3c = 0 …(1)



⇒ a + 3b - 2c = 5 …(2)



⇒ 2a + b + 4c = 8 …(3)


Solving equations 1 ,2,3, simultaneously we get:


a = 1,b = 2,c = 1



Ans:



Question 26.

If and the coordinates of A are (0, - 2, - 1), find the coordinates of B.


Answer:





∴ B(3, - 3,1)


Ans: B(3, - 3,1)



Question 27.

If A(2, 3, 4), B(5, 4, - 1), C(3, 6, 2) and D(1, 2, 0) be four points, show that is perpendicular to


Answer:








Hence,



Question 28.

Find the value of λ for which the vectors and are perpendicular to each other.


Answer:



Since these two vectors are perpendicular, their dot product is zero.








Ans:



Question 29.

Show that the vectors and form a right - angled triangle.


Answer:








Hence, the triangle is a right angled triangle at c



Question 30.

Three vertices of a triangle are A(0, - 1, - 2), B(3, 1, 4) and C(5, 7, 1). Show that it is a right - angled triangle. Also, find its other two angles.


Answer:
















Ans:45°,90°,45°



Question 31.

If the position vectors of the vertices
A, B and C of a ∆ABC be (1, 2, 3), ( - 1, 0, 0) and (0, 1, 2) respectively then find ∠ABC.


Answer:












Ans: = ∠ABC



Question 32.

If and are two unit vectors such that find


Answer:




⇒ cosθ = 1/2





Ans:



Question 33.

If and are two vectors such that then prove that vector is perpendicular to the vector


Answer:





NOW,





Hence,



Question 34.

If and then express in the form where and


Answer:

Let b1 = c and b2 = d






&





⇒ λ = 5/10 = 1/2






b1 + b2



Ans: