1. Evaluate the following integrals:
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2. Evaluate:
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3. Evaluate:
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Evaluate the following integrals (1 – 44):
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Given,
∫(2 – 3x)(3 + 2x)(1 – 2x) dx
= ∫(6 + 4x – 9x – 6x2)(1 – 2x) dx
= ∫(6 – 5x – 6x2)(1 – 2x) dx
= ∫(6 – 5x – 6x2 – 12x + 10x2 + 12x3) dx
= ∫(6 – 17x + 4x2 + 12x3) dx
Upon splitting the above, we have
= ∫6 dx – ∫17x dx + ∫4x2 dx + ∫12x3 dx
On integrating using formula,
∫xn dx = xn+1/n+1
we get
= 6x – 17/(1+1) x1+1 + 4/(2+1) x2+1 + 12/(3+1) x3+1 + c
= 6x – 17x2/2 + 4x3/3 + 3x4 + c
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Integrate the following integrals:
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Evaluate the following integrals:
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Therefore,
= cos (b – a)x + sin(b – a) log |sin(x – b)| + c, where c is an arbitrary constant.
Evaluate the following integrals:
dx
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Evaluate the following integrals:
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Evaluate the following integrals:
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By using,
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Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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Let sin x = t
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Evaluate the following integrals:
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We will solve I1 and I2 individually.
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Evaluate the following integrals:
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⇒ 1 = (A + B) x + (3A – 2B)
⇒ Then A + B = 0 … (1)
And 3A – 2B = 1 … (2)
Solving (1) and (2),
2 × (1) → 2A + 2B = 0
1 × (2) → 3A – 2B = 1
5A = 1
∴ A = 1/5
Substituting A value in (1),
Or I = log|(x – 2)/(x + 3)| + x + c
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Hence,
Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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5.
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Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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Evaluate the following integrals:
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The given equation can be written as,
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Now, substituting t as x – 1/x and z as x + 1/x we have
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We get,
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Evaluate the following integrals:
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