Chapter 8 Introduction to Trigonometry

Class 10^th NCERT Maths Book Solution

CBSE Class 10 Maths

NCERT Solution

Introduction to Trigonometry Exercise Ex. 8.2

Solution 1

Solution 2

Solution 3

Solution 4

Introduction to Trigonometry Exercise Ex. 8.3

Solution 1

We know that

Solution 2

We know that

Solution 3

(i) 9sec²A - 9tan²A
= 9(sec²A - tan²A)
= 9 (1) (as sec²A - tan²A = 1)
= 9
Hence alternative (B) is correct.

(ii) (1 + tanθ + secθ) (1 + cotθ - cosecθ)

Hence alternative (C) is correct.

(iii) (secA + tanA) (1 - sinA)

(iv)

Solution 4