ROUTERA


Chapter 10 Circles

Class 10th NCERT Maths Book Solution
CBSE Class 10 Maths
NCERT Solution


Circles Exercise Ex. 10.1

Solution 1

Solution 2

Solution 3


Solution 4

Circles Exercise Ex. 10.2

Solution 1

Solution 2

Solution 3

Solution 4

Solution 5

Solution 6

Solution 7



Solution 8

Solution 9






Solution 10

Solution 11

Since, ABCD is a parallelogram,

AB = CD                                                                (i)

BC = AD                                                                (ii)

Now, it can be observed that:

DR = DS                 (tangents on circle from point D)

CR = CQ                 (tangents on circle from point C)

BP = BQ                 (tangents on circle from point B)

AP = AS                 (tangents on circle from point A)

Adding all the above four equations,

DR + CR + BP + AP = DS + CQ + BQ + AS

(DR + CR) + (BP + AP) = (DS + AS) + (CQ + BQ)                 

CD + AB = AD + BC                                            (iii)

 

From equation (i) (ii)  and (ii):

         2AB = 2BC

         AB = BC

         AB = BC = CD = DA

         Hence, ABCD is a rhombus.

Solution 12





Solution 13